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A ball is thrown vertically upwards from the top of the tower at 4.9 m/s and the time t sec is 3 secs . what is the height of the tower ​

Answer»

s=ut+1/2at2so s is DISPLACEMENT which is height of the towerso, h= (-4.9)3+1/2*9.8*9. Use sign CONVENTION = 4.9(6) So the answer is 29.4 metersThanks a lotplease mark me as BRAINLIEST



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