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A ball is thrown vertically upwards from the ground. It crosses a point at the height of 25 m twice at an interval of4s. The ball was thrown with the velocity of(1) 20 m/s(2) 25 m/s(3) 30 m/s(4) 35 m/s |
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Answer» After reaching the maximum height , it falls for 2seconds to reach the 25 m height. Distance it has FALLEN is h = 0.5 gt^2 = 0.5*10* 4 =20 m. Maximum height is 25+20 = 45 m. Velocity at the bottom or the initial velocity is found from u^2 = 2gh = 2*10*45 =900 u = 30 m/s. Explanation: mark me BRAINLIEST if u WANT |
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