A ball is thrown vertically upwards and returns to the thrower after 4

1.	A ball is thrown vertically upwards and returns to the thrower after 4 sec (g=9.8 m/s2).
Answer» Explanation: Given: g=9.8 Total time=12 sec 1) Total time is 12 sec Time taken to go up=Time taken to get down So t=6sec and at max height v= 0 By equation of motion 0=u - gt( - SIGN for UPWARD direction) u= 9.8 (6) u=58.8 m/s 2) At max height v=0 u=58.8 t= 6 By 2nd equation of motion s=ut- 1/2gt2 s=(58.8×6)-1/2(9.8)(6×6) s=352.8- 176.4 s=176.4m 3) Ball reached max height in 6sec so, in 8SEC ball travelled for 2sec after reaching max height which gives u=0 t=2sec. s=? Again s=ut + 1/2gt2 ( + sign because ball is coming down) s=0 + 1/2(9.8)(2×2) s=19.6 m Read more on Brainly.in - brainly.in/question/671209#readmore

A ball is thrown vertically upwards and returns to the thrower after 4 sec (g=9.8 m/s2).

Answer»

Explanation:

Given: g=9.8

Total time=12 sec

1) Total time is 12 sec

Time taken to go up=Time taken to get down

So t=6sec

and at max height v= 0

By equation of motion

0=u - gt( - SIGN for UPWARD direction)

u= 9.8 (6)

u=58.8 m/s

2) At max height v=0

u=58.8

t= 6

By 2nd equation of motion

s=ut- 1/2gt2

s=(58.8×6)-1/2(9.8)(6×6)

s=352.8- 176.4

s=176.4m

3) Ball reached max height in 6sec

so, in 8SEC ball travelled for 2sec after reaching max height

which gives u=0

t=2sec. s=?

Again s=ut + 1/2gt2 ( + sign because ball is coming down)

s=0 + 1/2(9.8)(2×2)

s=19.6 m

Read more on Brainly.in - brainly.in/question/671209#readmore

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