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A ball is thrown vertically upward with initial speed 40 m/s. The distance travelled by the ball in last second of upward journey is (g = 10 m/s2) |
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Answer» Initial VELOCITY u=40Fianl velocity v=0Height, s=?By third equation of motionv 2 −u 2 =2gs0−40 2 =−2×10×ss= 20160 ⇒s=80m/sToatl distance travelled by stone = upward distance + downwars distance =2×s=160mTotal Diaplacement =0, SINCE the initial and final point is same.Explanation:this is the answer PLEASE mark as BRAINLIEST |
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