1.

a ball is thrown upwards with a velocity of 10m/s.find the maximum height reached by the ball and the time taken to come back to the thrower (g=10 m/s square)

Answer»

v=0g=10m/s²a= -10m/s²v²-u²=2ah=>(0)²-(10)²=2×(-10)×H=> -100= -20h=>h = -100/-20=5m



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