1.

A ball is thrown up with a speed of 0.5 m/s.(i) How high will it go before it begins to fall?​

Answer»

Answer:

0.0012M

Step-by-step explanation:

SOLUTION:

    velocity=0.5m/s

    final velocity=0

    acceleration DUE to gravity=g= -9.8m/s^{2 (it is TAKEN -ve as BODY moves  against the gravity)

    h=??

  • Formula:

   2gH=Vf^{2}-Vi^{2}

  • CALCULATION:  

     2(-9.8)H=(0)^2-(0.5)^2

    -19.6H=0-0.25

     H= -0.25/-19.6

     H=0.0012m

  • RESULT:

     IT WILL FALL FOR 0.0012METER.


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