A ball is thrown up caught by thrower after 4sec . How high did it go

1.	A ball is thrown up caught by thrower after 4sec . How high did it go and with what velocity was it thrown?
Answer» ANSWER: total time taken = 2u/g as g = 10 m/s^2 and total time taken is 4 sec, 4=2u/10 2u = 40 U= 20 m/s maximum height = u²/2g =400/20 = 20 m hope it helped and pleeeeeeeeeease mark as BRAINLIEST:)

A ball is thrown up caught by thrower after 4sec . How high did it go and with what velocity was it thrown?

Answer»

ANSWER:

total time taken = 2u/g

as g = 10 m/s^2

and total time taken is 4 sec,

4=2u/10

2u = 40

U= 20 m/s

maximum height = u²/2g

=400/20

= 20 m

hope it helped and pleeeeeeeeeease mark as BRAINLIEST:)

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A ball is thrown up caught by thrower after 4sec . How high did it go and with what velocity was it thrown?

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