1.

A ball is thrown straight up with a velocity of 12 m/s; what will be its velocity 2.0 s after being released?

Answer»

8m/s EXPLANATION:it takes 1.2 s to reach the TOP and then we have to FIND the velocity when it was moving down at time 0.8 SEC and by  v = u +at             v = 0 + 10 * 0.8              v = 8m/s



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