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A ball is thrown horizontally from the top of a tower and strikes the ground in 3 second at an angle of 30° with the vertical find the height of the tower and find the speed with which the body was projected |
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Answer» Explanation: Thrown horizontally: Vertical component of velocity present only due to acceleration due to gravity. H= 1/2*gt^2 H= 1/2*10*9 H= 45m Assuming HORIZONTAL velocity of PROJECTION of the body to be =u, the vertical component of velocity reached in moving for 3S =>v=gt=10×3=30m/s => tan30=1/√3=v/u u=√3×30 u=51.9615243m/s |
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