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A ball is throw with the velocity of 39.2m/s at an angle of 30° with the horizontal .Calculate the maximum height, time of flight & horizontal range of projectile. |
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Answer» in^2(X)/2G=(39.2)^2×(1/2)^2/2×9.8=19.6mt=4 seconds4H=Rtan (x)4×19.6=R×tan (30)R=135.7m✌ |
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