A ball is released at t =0 s from a high building.To find :AVERAGE power delivered in 1st, 2nd and 3rd second of time.Solution :When a ball is released from top of a high building from rest. The only force applicable on the ball is Gravitational force.All other FORCES like air RESISTANCE are neglected.So when a ball is released from rest.Its initial velocity is 0.So, u = 0 .From the formula of motion:(equation 1)heres = distance covered.u = initial velocity.t = time taken.a = acceleration.We know that initial velocity u = 0and in case of free fall,So, by equation 1,in 1 second (t=1 s) the distance covered by ball is:soin 2 SECONDS (t =2) the distance covered by ball is :in 3 seconds (t = 3) the distance covered by ball is:So,Distance covered in only 1st second is :Distance covered in only 2nd second is:Distance covered in only 3rd second is :We know that:Where in case of Gravitational force,Work done by gravity is :Work = mgh Where m = mass of body.g= gravitational acceleration.h = height of body.In all three cases time in work done is t = 1 second because we are calculating power in each second.pitting g =9.8 So,Power delivered in 1st second :Power delivered in 2nd second :Power delivered in 3rd second :