1.

A ball is projected with speed u at an angle `theta` to the horizontal. The range R of the projectile is given by `R=(u^(2) sin 2theta)/(g)` for which value of `theta` will the range be maximum for a given speed of projection? (Here g= constant)A. `pi/2 rad`B. `pi/4 rad`C. `pi/3 rad`D. `pi/6 rad`

Answer» Correct Answer - B
As `sin2theta le 1` so range will be maximum if `sin 2theta=1`. Therefore `2theta=pi/2 rArr theta=pi/4 rad`


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