1.

A ball is projected at some angle with ground such that it is at a particular height two times at `t = 4s` and `t = 6s`. Find the maximum height of the projecticle during the motion.A. `50 m`B. `80 m`C. `125 m`D. `180 m`

Answer» Correct Answer - C
`T = t_(1) + t_(2) 4 + 6 = 10s`
`10 = 2 (u sin theta)/(g) = rArr u sin theta = 50 m//s`
`H_("max") = (u^(2) sin^(2) theta)/(g) = 125 m`


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