A ball is kicked at an angle of 30° with the vertical. If the horizontal component of its velocity is 20 meters per second, what is its maximum height and the horizontal range?

A ball is kicked at an angle of 30° with the vertical. If the horizon

1.	A ball is kicked at an angle of 30° with the vertical. If the horizontal component of its velocity is 20 meters per second, what is its maximum height and the horizontal range?
Answer» if its KICKED at 30 with vertical MEANS angle with horizontal is 60.x COMPONENT of velocity never changes and is given 20.do 20=ucostheta20=ucos60therefore U = 40 .now u have u and theta just put the values and get the ans..max HEIGHT u^2 sin^2theta/2grange u^2 × 2sintheta cos theta/g

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A ball is kicked at an angle of 30° with the vertical. If the horizontal component of its velocity is 20 meters per second, what is its maximum height and the horizontal range?​

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A ball is kicked at an angle of 30° with the vertical. If the horizontal component of its velocity is 20 meters per second, what is its maximum height and the horizontal range?