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A ball is horizontally thrown from the top of staircase in such a way that it reach to the bottom of last step having height 20 cm and breadth 14 cm then find out initial velocity of body (staircase having six steps). |
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Answer» HORIZONTAL distance covered by ball =nb Vertical distance covered by ball =nh If the time taken to HIT the edge of nth STEP is t, then nb=ut nh=12gt2 Eliminating t, we GET, nh=12g(nbu)2 n=2hu2gb2 Same as EXAMPLE |
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