1.

A ball is horizontally thrown from the top of staircase in such a way that it reach to the bottom of last step having height 20 cm and breadth 14 cm then find out initial velocity of body (staircase having six steps).​

Answer»

HORIZONTAL distance covered by ball =nb

Vertical distance covered by ball =nh

If the time taken to HIT the edge of nth STEP is t, then

nb=ut

nh=12gt2

Eliminating t, we GET,

nh=12g(nbu)2

n=2hu2gb2

Same as EXAMPLE



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