1.

a ball is dropped from a height of 20m if its velocity increases uniformly at the rate of 10ms^2 with what velocity will it strike the ground? ​

Answer»

ong>ANSWER:

Given :

a = 10 m/s²

s = 20 m

u = 0 m/s

So applying third equation of MOTION :

v² - u² = 2as

⇒ v² - 0² = 2 × 10 × 20

⇒ v² = 400

⇒ v = √400

⇒ v = 20 m/s

Hence, the velocity at which the ball will strike the GROUND is 20 m/s.

Some Important Formulas :

  • v = u + at
  • v² - u² = 2as
  • s = UT + ½at²
  • Average velocity = ∆x/∆t
  • Average Speed = Total Path/Total Time
  • Instantaneous velocity = dx/dt
  • Averages acceleration = ∆v/∆t
  • Instantaneous acceleration = dv/dt
  • ∆x = x_2 - x_1


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