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A ball is dropped from a height of `20 m` and rebounds with a velocity which is `3/4` of the velocity with which it hits the ground. What is the time interval between the first and second bunces `(g=10m//s^(2))`A. `3` secB. `4` secC. `5` secD. `6` sec |
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Answer» Correct Answer - A Velocity after collision `v=(3)/(4) xx sqrt(2xx10 xx 20)=15 m//s t=(2u)/(g)=3sec`. |
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