1.

A ball falls off a table and reaches the ground in 1s. Assuming g =10m/s², calculate its speed on reaching the ground and the height of the table.

Answer»

Here are the formula that you should use:

dv = gdt

ds = t dv = gtdt

To get the values of V and S, integrate the equations. Thus:

V = gt + C; where g is the acceleration of GRAVITY which as you said shouh be taken as 10m’SEC^2, t is the TIME duration equal to 1 second and V = the velocity as the ball hits the ground. When t = 0, V = 0 hence the CONSTANT of integration C is 0. Thus the equation for finding V is;

V = gt.

S = (1/2)gt^2 + C; where S is the HEIGHT of the fall which is the height of the table when t = 1 sec and C is the constant of integration. When t is 0, S is 0 hence C is 0 thus

S = (1/2)gt^2


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