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A ball dropped from the top of the building reaches the ground in 6 seconds. Find the velocity with which it will hit the ground if value of g is 9.8 ms-1 |
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Answer» Answer: In the present event a BALL is being dropped (the term means that initial velocity=0) from a height h h = 19.6 m = 2 times the numerical value of g, the acceleration due to gravity we know how accelerations OPERATE ..it will add per SEC the value of g to the velocity v = g.t but the time taken to cover h =19.6 m ; using h = (1/2) g . t^2 t = sqrt ( 2.h /g) = 2 so the velocity of striking the ground v = 9.8 m/s^2 x 2 s = 19.6 m/ Explanation: |
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