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A ball dropped from 20g drop from height of 50m what will be the height of roof |
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Answer» v2- U2 = 2as a= ACCELERATION s= displacement u=INITIAL velocity v=final velocity If the body is freely falling under gravity then this equation can be modified as v2- u2 = 2gh h= height from which body is dropped g=9.8 m/s2 Now Come To Your Question According to you question body is dropped from height of 10m so we can consider its initial velicity as zero h=10m u=0 g=acceleration due to gravity on earth which is equal to 9.8 m/s2 Now PUT the values of { height, initial velocity and acceleration due to gravity in third equation of motion } i.e v2- u2 = 2gExplanation: |
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