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A ball 10 kg hits a hard surface at 60°to normal speed 5m/s and rebounds with 3m/s at same angle if bal remains in contact for 0.1 seconds ,what force does itexert

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10 N

as average FORCE= ΔP/Δt                  where P is momentum

so we have m(v2-v1)/0.01                        where m is MASS of ball of in kg

so we have (0.01*10)/0.01 = 10 N



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