1.

a bag contains 6 red balls and some blue balls. If the probability of drawing a blue ball from the bag is twice that of a red ball. Then find the number of blue balls in the bag​

Answer»

Answer:

X=10.

Step-by-step explanation:

number of RED balls = 5

number of BLUE balls = x

N(s)=5+x

•p(E)=n(e)/n(s)

p (getting red balls) =5/ 5 + 6

p (getting blueborne) =x/ 5 + 6

p (blue balls) = 2X (red balls)

x / 5 + x = 2× 5 / 5 +x

the 5+x is equal in both at denominator so it is cancelled.

then,

x=2×5

x=10.

hence,

number of balls in the back =10.

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