A bag contains 4 white and 5 red marbles. Two marbles are drawn one af

1.	A bag contains 4 white and 5 red marbles. Two marbles are drawn one after the 1 other without changing. Find the probability of getting both as white marbles.
Answer» n = (4W + 5 R) = 9 ways to draw one ball from 9 balls Let probability of drawing white and red marbles be P(W) and P(R) P(drawing 2 white marbles one after the other) = P (2W) = P (white marble in I draw) and P (drawing white marble in II draw) P(WI ∩ WII) = P (WI) P (WII/ WI) P(A ∩ B) = P(A) P(B/A) = 4/9 x 3/8 = 12/72 = 1/6 Here, first drawn ball is not replaced.

A bag contains 4 white and 5 red marbles. Two marbles are drawn one after the 1 other without changing. Find the probability of getting both as white marbles.

Answer»

n = (4W + 5 R) = 9 ways to draw one ball from 9 balls

Let probability of drawing white and red marbles be P(W) and P(R)

P(drawing 2 white marbles one after the other)

= P (2W) = P

(white marble in I draw) and P (drawing white marble in II draw)

P(WI ∩ WII) = P (WI) P (WII/ WI)

P(A ∩ B) = P(A) P(B/A)

= 4/9 x 3/8 = 12/72 = 1/6

Here, first drawn ball is not replaced.

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A bag contains 4 white and 5 red marbles. Two marbles are drawn one after the 1 other without changing. Find the probability of getting both as white marbles.

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