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a+b+x a b x2a+b+2x 2a b 2x |
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Answer» (a) 1/(a+b+x)=1/a + 1/b + 1/x1/(a+b+x)=(bx+ax+ab)/abxabx=abx+a2x+a2b+b2x+abx+ab2+bx2+ax2+abxax2+bx2+a2x+abx+abx+b2x+a2b+ab2=0x2(a+b)+ax(a+b)+bx(a+b)+ab(a+b)=0(a+b)(x2+ax+bx+ab)=0since, a+b!=0so, x2+ax+bx+ab=0x(x+a)+b(x+a)=0(x+a)(x+b)=0x=-a,-b (b)1/2a+b+2x-1/2x = 1/2a+1/b 2x-2a-b-2x/4ax+2bx+4x^2 = 2a+b/2ab - (2a+b)/4ax+2bx+4x^2 = 2a+b/2ab-2ab = 4ax+2bx+4x^2 4x^2+2bx+4ax+2ab = 02x (2x+b)+2a (2x+b) = 0x=-a or -b/2 |
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