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a,b,c together can do a piece of work in 10 days . a takes twice as long as b and c together . b takes as long as a and c together . how much time can c alone take to complete the work |
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Answer» Answer: according to 1ST conditiona+b+c=10 according to 2nd conditionStep-by-step EXPLANATION:
now from point 1 and 2, we geta+b+c=10 since,b+c =a therefore we PUT VALUE of b+c as a thus a+a=10 2a=10 a=10÷2 thus a=5 now we substitute the value of a=5 a+b+c=10 5+b+c=10 b+c=10-5 b+c=5 according to 3rd condition b take same time as ctherefore dividing the value of b+c by 2 thus 5÷2 = 2.5 therefore c take 2.5 days ALONE |
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