1.

A B C play a game . B starts the game getting a sum of 9 is considered to be a winner 2 dice are thrown . find the probability of A B C winning​

Answer»

<P>Answer:

ANSWER

Let  S  denote  the  success  (getting  a  ‘6’)  and  F  denote  the  FAILURE  (not  getting  a  ‘6’)  .  

Thus, P(S)=61=p,  P(F)=65=q

P(A wins  in  first  THROW)=P(S)=p

P(A  wins  in  THIRD  throw)=P(FFS)=qqp

P(A  wins  in  fifth  throw)=P(FFFFS)=qqqqp

So,  P(A  wins)=p+qqp+qqqqp+…

=p(1+q2+q4+…)

=1−q2p=1−362561=116

P(B  wins)=1–P(A  wins)

P(B  wins)  =1−116=115

So,  P(A  wins)=116 ,  P(B  wins)=115


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