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A,B,C,D are angles of a cyclic quadrilateral then sinA+sinB- sinC-sinD |
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Answer» Answer: 0 Step-by-step EXPLANATION: In a CYCLIC quadrilateral, opposite angles sum is 180A + C = 180 --------------(i)B + D = 180 --------------(II)
From equation firstA=180-CsinA=sin (180-C)
sinA=sinCsinA-sinC=0similarly From equation second sinB-sinD=0L.H.S= sinA+sinB-sinC-sinD= (sinA-sinC)+sinB-sinD
=0 |
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