1.

A,B,C,D are angles of a cyclic quadrilateral then sinA+sinB- sinC-sinD​

Answer»

Answer:

0

Step-by-step EXPLANATION:

In a CYCLIC quadrilateral, opposite angles sum is 180

A + C = 180 --------------(i)

B + D = 180 --------------(II)

From equation first

A=180-C

sinA=sin (180-C)

sinA=sinC

sinA-sinC=0

similarly From equation second

sinB-sinD=0

L.H.S= sinA+sinB-sinC-sinD

= (sinA-sinC)+sinB-sinD

=0



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