1.

A+b+c=0 then proved that xyz=1​

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Answer:

From the following, we need to find the values of x,y, and z:

a x =b , b y =c , c z =a

From AX =  b, we get x  =b/a -------------------------- (i)

From by = c, we get y  =c/b ---------------------------(II)

From cz = a, we get z = c/a ---------------------------(iii)

Multiplying the left HAND sides and RIGHT hand sides of (i), (ii) and (iii) we get

xyz=(b/a)*(c/b)*(c/a)

When we simplify, we find that xyz=1. Hence proved.

Step-by-step explanation:

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