1.

A/ax-1 + b/bx-1 =a+b slove by factorization

Answer» ONG>Step-by-step explanation:

Given:

aax−1+bbx−1=a+b

Subtract aax−1+bbx−1 from both SIDES to get:

0=a+b−aax−1−bbx−1

Multiply through by (ax−1)(bx−1) to get:

0=(a+b)(ax−1)(bx−1)−a(bx−1)−b(ax−1)

0=(a+b)(abx2−(a+b)X+1)−a(bx−1)−b(ax−1)

0=(a+b)(abx2−(a+b)x)+


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