1.

a aq naoh b (a ketone) i2 / naoh chi3 + sodium propanoatea aq naoh b (a ketone) i2 / naoh chi3 + sodium propanoate

Answer»

This is iodoform REACTION.(MAINLY answered by methyl KETONES and methyl carbinols)

Since sodium propanoate is LIBERATED here, the ketone will be butan-2-one.

Ans-Butan-2-one

STRUCTURE


CH3-CO-CH2-CH3



Discussion

No Comment Found