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a aq naoh b (a ketone) i2 / naoh chi3 + sodium propanoatea aq naoh b (a ketone) i2 / naoh chi3 + sodium propanoate |
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Answer» This is iodoform REACTION.(MAINLY answered by methyl KETONES and methyl carbinols) Since sodium propanoate is LIBERATED here, the ketone will be butan-2-one. Ans-Butan-2-one STRUCTURE CH3-CO-CH2-CH3 |
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