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A and B together can do e pieu of work incan finish it in 30 daysIn how many days con H alone finish the wook10 dayswhile B alone |
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Answer» Answer: IN ONE DAY they do: A + B= 1/30 of the job or A=1/30-B A + C= 1/20 of the job or A=1/20-C C + B= 1/24 of the job or C=1/24-B 1/30-B =1/20-1/24 + B B = (1/30 - 1/20 + 1/24 ) / 2 So B = 1/ 80 Then we find C = 1/24–1/80 = (20 - 6) /480 = 14/480 C = 7/240 then we find A=1/30-B = 1/30 -1/ 80 A = 5 /240 Now with their rendiment in ten days they do together: = 10 × ( 5/240 + 1/80 + 7/ 240) = 15/24 What is left to do is by A only is: 1- 15/24 = 3/8 of the job Since A does 5/ 240 PER day we calculate: X = (3/8) / (5/240) X= 18 Whic means that after the FIRST days that they work together the job will be finished by A alone in another 18 days. |
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