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A and B can do a piece of work in 40 days , B and C in 30 days and C and A in 24 days. How long will it take to do the work together? How much time will each of them will take to finish it alone |
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Answer» Answer: here given 40(a+b)=1.........(1) 30(c+a)=1..........(3) let T(a+b+c)=1 we wanna find value of t. LCM in equation 1,2,and 3 is 120. therefore, (1)×3=>120(a+b)=3............(4) (2)×4=>120(b+c)=4.............(5) (3)×4=>120(c+a)=4..............(6) adding equation 4,5 and 6 we get, 120(a+b+b+c+c+a)= 3+4+4 =>120 ×2 (a+b+c)= 11 => 240/11(a+b+c)= 1 => 21.81 (a+b+c) =1 the value of t is 21.81 or 22 days approximately. so if they WORK together it will take 22 day. try SECOND question as we have value of a+b+c.
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