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A and B can do a piece of work in 18 days. B and C together can do it in 30 days. If A is twice as good a workman as C, find in how many days B alone can do the work?1. 90 days2. 80 days3. 75 days4. 100 days |
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Answer» Correct Answer - Option 1 : 90 days Given: A and B can do a piece of work in 18 days. B and C do it in 30 days. A is twice as good a workman as C. Calculation: Let total work is LCM of (18, 30) equal to 90 units. According to the question The efficiency of A and B together is ⇒ 90/18 ⇒ 5 units The efficiency of B and C together is ⇒ 90/30 ⇒ 3 units The difference between the efficiency of A and C is ⇒ 5 - 3 ⇒ 2 units The ratio of the efficiency of A and C is ⇒ 2 : 1 Now, We say that the efficiency of A is 4 units and C is 2 units, then The efficiency of B is ⇒ 5 - 4 ⇒ 1 units So, The time taken by B to complete the work is ⇒ 90/1 ⇒ 90 days ∴ B alone completes the whole work in 90 days. |
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