1.

A and B can do a piece of work in 18 days. B and C together can do it in 30 days. If A is twice as good a workman as C, find in how many days B alone can do the work?1. 90 days2. 80 days3. 75 days4. 100 days

Answer» Correct Answer - Option 1 : 90 days

Given: 

A and B can do a piece of work in 18 days. B and C do it in 30 days.

A is twice as good a workman as C.

Calculation: 

Let total work is LCM of (18, 30) equal to 90 units. 

According to the question

The efficiency of A and B together is 

⇒ 90/18

⇒ 5 units

The efficiency of B and C together is 

⇒ 90/30

⇒ 3 units

The difference between the efficiency of A and C is 

⇒ 5 - 3

⇒ 2 units

The ratio of the efficiency of A and C is 

⇒ 2 : 1

Now, We say that the efficiency of A is 4 units and C is 2 units, then 

The efficiency of B is 

⇒ 5 - 4

⇒ 1 units 

So, 

The time taken by B to complete the work is 

⇒ 90/1

⇒ 90 days

∴ B alone completes the whole work in 90 days.



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