A and b are zeros of polynomial 6x2+7x+3 than find a2+b2

1.	A and b are zeros of polynomial 6x2+7x+3 than find a2+b2
Answer» if a and b are the ZEROS of polynomial then it will divide 6×2+7x+3 by leaving 0 as remainder x=a then 12+7a+3=0 15+7a=0. 1st equation x=b 12+7b+3=0 15+7b=0. 2ND equation adding both 1AND 2nd equation 15+7a+15+7b=0 30+7(a+b)=0 a+b=-30/7 2a+2b=-60/7. (multiplying by 2 on both SIDES

Answer»

if a and b are the ZEROS of polynomial then it will divide 6×2+7x+3 by leaving 0 as remainder

x=a then 12+7a+3=0

15+7a=0. 1st equation

x=b

12+7b+3=0

15+7b=0. 2ND equation

adding both 1AND 2nd equation

15+7a+15+7b=0

30+7(a+b)=0

a+b=-30/7

2a+2b=-60/7. (multiplying by 2 on both SIDES

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A and b are zeros of polynomial 6x2+7x+3 than find a2+b2​

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A and b are zeros of polynomial 6x2+7x+3 than find a2+b2