(A) : Always |(dbarv)/(dt)|=(d)/(dt)|vecv|, where vecv hasits usual meaning (R ) : Acceleration is rate of change of velocity.

(A) : Always |(dbarv)/(dt)|=(d)/(dt)|vecv|, where vecv hasits usual me

1.	(A) : Always \|(dbarv)/(dt)\|=(d)/(dt)\|vecv\|, where vecv hasits usual meaning (R ) : Acceleration is rate of change of velocity.
Answer» Both (A) and (R ) are true and (R ) is the CORRECT explanation of (A) Both (A) and (R ) are true and (R ) is not the correct explanation of (A) (A) is true but (R ) is false (A) is false but (R ) is true ANSWER :D