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A alone complete a piece of work in 10/3 days, B and C together can complete the same work in 20/9 days. If B is 25% more efficient than C. Then in how many days A, B, and C together complete the same work?1. 5/9 days2. 10/7 days3. 4/3 days4. 3/4 days5. 9/7 days |
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Answer» Correct Answer - Option 3 : 4/3 days Given: Time to complete work by A = 10/3 days Time to complete work by B and C together = 20/9 days Efficiency of B = 125% efficient than C Concept used: One day work = 1/Total days to complete work Total number of days to complete work = Work/One day work Calculation: Time to complete work by A = 10/3 days One day work of A = 1/(10/3) ⇒ One day work of A = 3/10 Time to complete work by B and C together = 20/9 days ⇒ One day work of B and C together = 1/(20/9) ⇒ One day work of B and C together = 9/20 One day work to complete A, B, and C together = One day work of A + One day work of B and C together ⇒ Required one day work = 3/10 + 9/20 ⇒ Required one day work = (6 + 9)/20 ⇒ Required one day work = 15/20 ⇒ Required one day work = 3/4 Total number of days to complete work = Work/One day work ⇒ Required total days = 1/(3/4) ⇒ Required total days = 4/3 days ∴ 4/3 day to complete same work by A, B, and C. |
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