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(a-a^-2)/(root a-root(a^-1)-2/(root a^3)-(1-a^2)/(root a+root(a^-1)) |
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Answer» The cubic EQUATION whose TWO roots are 1, 3 + 2/ is — (A) x3-lx2+ 12*- 13 = 0 (B) x2 ... □-(f)- 28 (a-d) - a(a + d) => a(a2-D2) = 28 => 4(16 -d2) = 28 => 16-d2 = 7 ... please mark like and follow me |
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