Saved Bookmarks
| 1. |
A 66 % efficient transformer is working on 110 V and 2.2 kW power.If current in secondary coil is 6.0 A, calculate (i) current in primary coil and (ii) voltage across secondary coil. |
|
Answer» Here, `eta = 66//100, E_(p) = 110 V`, `P_(p) = 2.2 kW = 2200 W` `I_(s) = 6.0 A, I_(p) = ?, E_(s) = ?` As `P_(p) = E_(p) I_(p) :. I_(p) = P_(p)//E_(p) = (2200)/(110) = 20 A` As `eta = (E_(s) I_(s))/(E_(p) I_(p)) :. (66)/(100) = (E_(s) xx 6)/(2200)` `E_(s) = (66 xx 2200)/(100 xx 6) = 242 V` |
|