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A 60 kg man stands on elevator floor the elevator is going up with constant acceleration of 1.96 metres per second square percentage change in the Apparent weight of the person is |
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Answer» 19.6% Explanation: The apparent weight of the man in standing elevator, W=mg, W=60(10)=600N Now if the elevator is accelerating upwards then the apparent weight of the man, W'=m(g+a) W'=m(10+1.96) W'=60(11.96)=717.6 RELATIVE CHANGE in apparent weight=(W'-W)÷W (717.6-600)÷600=0.196 PERCENTAGE relative change= Relative change×100 0.196×100=19.6 |
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