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A 6 ohm resistance wire is doubled up by folding . Calculate the new resistance of wire

Answer» Resistance=ρL/AHere, Resistance=6ohmTherefore,6=ρL/AIn second case, Resistance,R\'=ρL\'/A\'As the wire is doubled so L\'=L/2, A\'=2ASo new resistance,R\'=ρL/4A=(1/4)ρL/ABut\xa0ρL/A=6So, R\'=6/4=1.5Ω


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