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A 6 digit number always formed by repeating 3 digits like xyzxyz is:a) Always divisible by 7b) Divisible by 7 and 3c) Always divisible by 11d) Divisible by 11 and 7Which of the above statement is correct?1. c2. b3. a4. d |
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Answer» Correct Answer - Option 4 : d Concept used: Divisibility rule of 11: If the difference of the alternating sum of the digits of a number is a multiple of 11, then the number is divisible by 11 Divisibility rule of 7: Take the last digit of the number, double it then subtract the result from the rest of the number, If the resulting number is divisible by 7 then original number is divisible by 7 Calculation: Checking above given digits xyzxyz Adding digits alternately then we got (x + z + y) and (y + x + z) The difference between the number is 0 which is multiple of 11 The number formed may or may not be divisible by 3 The number formed is always divisible by 7 Taking any number 142142, 343343 etc these number is not divisible by 3 but divisible by 7 ∴ The above pattern of the number is always divisible by 7 and 11 |
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