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A 5m long vertical tube having cross sectional area 200 cm2 is placed in a water. It is filled with 15⁰C water, with the bottom closed and the top open to 100kpa atmosphere. How much water is present in the tube ? |
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Answer» We know that Mass = Volume x density m = (A x H).\(\rho\) m = 200 x 10-4 x 5 x 997 m = 997 x 10-1 m = 99.7 kg |
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