A 5kg block is acted upon by two perpendicular forces of 8 N and 6 N .

1.	A 5kg block is acted upon by two perpendicular forces of 8 N and 6 N .Find themagnitude and direction of the acceleration produced in the block.
Answer» ANSWER body of mass m is 5 kg R= (8) 2 +(−16 2 )= 64+36 =10N θis angle MADE by force of 8 N θ=tan −1 (−6/8)=−36.87 0 the negative sign indicates theta clockwise direction respect to the force of MAGNITUDE 8N force is m X a a=f/m=10/5=2ms −2

A 5kg block is acted upon by two perpendicular forces of 8 N and 6 N .Find themagnitude and direction of the acceleration produced in the block.

Answer»

ANSWER

body of mass m is 5 kg

(8)

+(−16

64+36

=10N

θis angle MADE by force of 8 N

θ=tan

−1

(−6/8)=−36.87

the negative sign indicates theta clockwise direction respect to the force of MAGNITUDE 8N

force is m X a

a=f/m=10/5=2ms

−2

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A 5kg block is acted upon by two perpendicular forces of 8 N and 6 N .Find themagnitude and direction of the acceleration produced in the block.​

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A 5kg block is acted upon by two perpendicular forces of 8 N and 6 N .Find themagnitude and direction of the acceleration produced in the block.