1.

A 500g tooth paste sample has 0.2g fluoride concentration. The concentration of F^(-) ion in terms of ppm level is 100 xx X. What is the value of X ?

Answer»

<P>

Solution :Mass of solute = 0.2 GM in 500gm tooth PASTE. So concentration per kg `= ( 0.2) / ( 500) xx 100` gm `= 0.4 g m // kg `
Since to find the level of `F^(-) `ion in PPM we NEED to convert the conc. In Mg AS
Conc of `F^(-)`ion in `Mg //Kg = 0.4 xx 100 mg // g m = 400 mg // kg `
Hence level of `F^(-)`ion in ppm `= ( " weight of solute")/("weigth of ion") = 400 mg //kg = 400 p p m = 100 xx 4 `p p m


Discussion

No Comment Found

Related InterviewSolutions