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a 50 microfarad capacitor in a defibrillator is charged to 3000v. the energy stored in the capacitor is sent through the victim during a pulse of duration 2 ms. the power of the pulse is close to? |
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Answer» Hii FRIEND, # Answer- 112.5kW # GIVEN- C = 50 microfarad = 50×10^-6 farad V = 3000 V t = 2 ms = 2×10^-3 s # Formula- Power of the pulse is given by, Power = 1/2 CV^2 / t Power = (1/2×50×10^-6×3000^2)/(2×10^-3) Power = 112500 W Power = 112.5 kW Power of the pulse is close to 112kW. Thanks for asking... |
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