a 50 micro farad capacitor is charged to 3000v. The energy stored in c

1.	a 50 micro farad capacitor is charged to 3000v. The energy stored in capacitor is sent through victim during pulse of duration 2ms.the power of pulse is?
Answer» <P>The definition of "Capacitance" is the ratio of CHANGE in electric charge to the change in electric potential. THEREFORE, C = Q/V. Which means that the electric charge, Q = C.V = $5010^{-6}<klux>3000</klux>=0.15$ Coulomb. Energy stored in the capacitor can be explained as the work done. Since the definition of "Voltage" is the energy stored per unit charge, therefore, *E = Q.V = 0.153000 = 450 J.** Power is the energy per unit time. Therefore, P = E/t = $\frac{450}{2*10^-3}=225KWatt$

a 50 micro farad capacitor is charged to 3000v. The energy stored in capacitor is sent through victim during pulse of duration 2ms.the power of pulse is?

Answer»

<P>The definition of "Capacitance" is the ratio of CHANGE in electric charge to the change in electric potential.

THEREFORE, C = Q/V. Which means that the electric charge, Q = C.V = $50*10^{-6}*<klux>3000</klux>=0.15$ Coulomb.

Energy stored in the capacitor can be explained as the work done. Since the definition of "Voltage" is the energy stored per unit charge, therefore, E = Q.V = 0.15*3000 = 450 J.

Power is the energy per unit time. Therefore, P = E/t = $\frac{450}{2*10^-3}=225KWatt$

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