A 5 MeV proton moves vertically downward through a magnetic field of induction `1.5 "weber"//m^(2)` pointing horizontally from south to north. The force acting on the proton, mass of proton `= 1.6 × 10–27 kg`. will be A. `7.44 xx 10^(-12)N`B. `3.1 xx 10^(-12) N`C. `5 xx 10^(-12) N`D. `6 xx 10^(-12) N`

A 5 MeV proton moves vertically downward through a magnetic field of i

1.	A 5 MeV proton moves vertically downward through a magnetic field of induction `1.5 "weber"//m^(2)` pointing horizontally from south to north. The force acting on the proton, mass of proton `= 1.6 × 10–27 kg`. will be A. `7.44 xx 10^(-12)N`B. `3.1 xx 10^(-12) N`C. `5 xx 10^(-12) N`D. `6 xx 10^(-12) N`
Answer» Correct Answer - A

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