1.

A 5 kg shell is fired with a muzzle velocity of 700m/sec from a gun barrel 2.4 m long. The value of impluse is

Answer»

Answer:

MASS of the bullet m = 5 kg

Velocity if the bullet V = 700 m /sec

Initial velocity of the bullet U = 0 m/sec ( at rest )

DISTANCE s = 2.4 m

From third equation of motion = v²=u²-2as

So , 700²=0²+2×a×2.4

So acceleration of the bullet will be =102083.33m/s²

Explanation:

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