A 5.0 cm cubeof substancehas itsupper facedisplaced by 0.65 cm, bya tangentialforce of 0.25 N. Calculatethe modulusof rigidity of rigidityof thesubstance.

A 5.0 cm cubeof substancehas itsupper facedisplaced by 0.65 cm, bya ta

1.	A 5.0 cm cubeof substancehas itsupper facedisplaced by 0.65 cm, bya tangentialforce of 0.25 N. Calculatethe modulusof rigidity of rigidityof thesubstance.
Answer» SOLUTION :`G=(FL)/(AL), A=L^(2) , G=(FL)/(L^(2)l)=(F)/(Ll)` Here, `L=5.0xx10^(-2)m` `l=0.65xx10^(-2)m, F=0.25N`. `G=(0.25)/(5.0xx10^(-2) xx 0.65xx10^(-2)) =(0.25 xx 10^(4))/(3.25)` `=769.2Nm^(-2)`