1.

A^4-18a^2-16=0plz slove this quadratic equation??​

Answer»

Answer:

a^4-18a^2-16=0

d=260=b^2-4ac

a^2=(18+\sqrt{388})/2 or a^2=(18-\sqrt{388})/2 this would be rejected as a SQ cannot be negative

thus a= root of (18+\sqrt{388})/2



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